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MT4 dual thrust系统原形源码

avatar 编程逆袭仔 | 7960 人阅读 | 18 人评论 | 2013-11-22

//dual thrust系统原形源码
Inputs: K1(.5),K2(.5),Mday(1),Nday(1);
Vars: BuyRange(0), SellRange(0);
Vars: BuyTrig(0),SellTrig(0);
Vars: HH(0),LL(0),HC(0),LC(0);
If CurrentBar > 1 Then Begin
HH = Highest(High,Mday);
HC = Highest(Close,Mday);
LL = Lowest(Low,Mday);
LC = Lowest(Close,Mday);
If (HH - LC) >= (HC - LL) Then Begin
SellRange = HH - LC;
End Else Begin
SellRange = HC - LL;
End;
HH = Highest(High,Nday);
HC = Highest(Close,Nday);
LL = Lowest(Low,Nday);
LC = Lowest(Close,Nday);
If (HH - LC) >= (HC - LL) Then Begin
BuyRange = HH - LC;
End Else Begin
BuyRange = HC - LL;
End;
BuyTrig = K1*BuyRange;
SellTrig = K2*SellRange;
If MarketPosition = 0 Then Begin
Buy at Open of next bar + BuyTrig Stop;
Sell at Open of next bar - SellTrig Stop;
End;
If MarketPosition = -1 Then Begin
Buy at Open of next bar + Buytrig Stop;
End;
If MarketPosition = 1 Then Begin
Sell at Open of next bar - SellTrig Stop;
End;
End;
""
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评论|共 18 个

jtkeutue

发表于 2014-11-12 16:40:32 | 显示全部楼层

下了  的确不错

xwfboy

发表于 2014-11-17 11:37:04 | 显示全部楼层


继续,学习了

yjogukiv

发表于 2014-11-20 00:31:25 | 显示全部楼层

看看吧,谢谢分享

聋鸢

发表于 2014-11-21 23:05:43 | 显示全部楼层

没有使用说明书

hawking473

发表于 2014-11-24 04:11:05 | 显示全部楼层

亏损中……………………

ainiya1b

发表于 2020-5-1 20:03:22 | 显示全部楼层

LZ说的很不错

12321312312

发表于 2020-5-1 21:58:54 | 显示全部楼层

楼主大方666

zjn1688

发表于 2020-7-11 21:13:44 | 显示全部楼层

谢谢楼主分享

april

发表于 2020-7-13 12:36:08 | 显示全部楼层

谢谢楼主分享

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